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Re: Lexical environment of method

    Date: Mon, 12 Mar 90 19:18:18 -0500
    From: kanderso@DINO.BBN.COM

    I am confused by your example, but if you want a lexical function
    that references the instance variables of an instance, you just have
    the instance create the closure:

    (defflavor widget
       (ivar "puzzle"))

    (defmethod (setup-fn widget) ()
      (setf fn #'(lambda () ... what you want done...)))

    (defmethod (use-fn widget) ()
      ... (funcall fn) ...)

This is completely correct.

    If you really want top level defun-in-flavor, like:

    (defun-in-flavor (fun widget) ()

    then you can try:

    (defmethod (setup-fn widget) ()
      (setf fn #'(defun-in-flavor fun widget)))

In the lexical environment inside the method body, #'FUN is exactly equivalent to
#'(DEFUN-IN-FLAVOR FUN WIDGET), except you don't have to go through this

    (defmethod (use-fn widget) ()
      ... (funcall fn self sys:self-mapping-table) ...)

You can just say (FUNCALL FN), or, better yet, (FUNCALL (WIDGET-FN WIDGET)).
That's because #'FUN is actually a lexical closure of

   #'(lambda (&rest args)
       (apply #'(defun-in-flavor fun widget) self self-mapping-table args))

which is what you want almost all the time.  For example, you can pass #'FUN to
things like MAP and PROCESS-WAIT, which you could not do with your FN above.)

[It should set your hackles on end when you see internal things like
SELF-MAPPING-TABLE and #'(DEFUN-IN-FLAVOR ...) in your code.]