speed of compiled funcalls

[Gyro at MIT-AI (Scott W. Layson)]

This isn't a bug, but I didn't know whom else to ask, so:

I have a macro that in normal use generates a lot of stuff of the form
(funcall #'foo bar)
  and
(funcall #'(lambda (snrk) (glop snrk 3)) cruft)


Should I bother to make the macro smart enough to turn this into
(foo bar)
  and 
(glop cruft 3)
or is the compiler smart enough to do the equivalent thing for me?