Re: (tyi foo) vs. (funcall foo ':tyi)

[JIS@MIT-AI]

CC: (BUG LISPM) at MIT-AI

		FOO

Rubout handlers shouldn't effect the operations of a simple
tyi.  I can see no problem (except some (a lot) of code may
have to be fixed).  with allowing the :tyi message be
semantically equivalent to the TYI function. There should be
a different message that does what the TYI message does now.
If this is too much work, then :TYI message can remain the
same and a new message be added to do what the TYI function
does now, in otherwords what I object to is that the TYI
function does actual work, instead it should be just sending
a message.

		-Jeff